UI: Remove redundant view reference in view items
The new view item base class already holds a reference to the view, no need to have one in the derived class as well.
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@ -36,8 +36,6 @@ class AbstractGridViewItem : public AbstractViewItem {
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friend class AbstractGridView;
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friend class GridViewLayoutBuilder;
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const AbstractGridView *view_;
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protected:
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/** Reference to a string that uniquely identifies this item in the view. */
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StringRef identifier_{};
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@ -29,8 +29,6 @@ AbstractGridViewItem &AbstractGridView::add_item(std::unique_ptr<AbstractGridVie
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items_.append(std::move(item));
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AbstractGridViewItem &added_item = *items_.last();
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added_item.view_ = this;
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item_map_.add(added_item.identifier_, &added_item);
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register_item(added_item);
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@ -181,7 +179,7 @@ const AbstractGridView &AbstractGridViewItem::get_view() const
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throw std::runtime_error(
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"Invalid state, item must be added through AbstractGridView::add_item()");
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}
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return *view_;
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return dynamic_cast<AbstractGridView &>(*view_);
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}
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/* ---------------------------------------------------------------------- */
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